As the name suggests this type of series are formed with a common rule between pairs, triplets or quadruplets in the series. Let’s start with a simple example

1, 2, 4, 5, 9, 10, 37, ?

Notice the following

(1, 2), (4, 5), (9, 10) have the second number in the pair as the mathematical increment (+1) of the first number. Consequently the next number in the series is 37 + 1 = 38.

Now, let’s practice with a few more examples representative of what you may encounter in the actual IPAT.

Q) 3, 9, 2, 4, 5, 25, 11, ?

solution

As we observe in (3,9), (2,4), (5,25) the second number in the pair is the square of the first number, consequently the next number in the series is 11×11 = 121

Q) 1, 1, 2, 2, 11, 13, 6, 4, 10, 5, 2, ?

solution

(1,1,2), (2,11,13), (6,4,10) we observe that the third number in each triplet is the sum of the first two numbers. Consequently, the next number in the series would be 5 + 2 = 7.

Q) 1, 7, 9, 1, 6, 2, 1, 4, 3, ?

solution

(1,7,9) (1,6,2) (1,4,3), we observe that the first number in each triplet is 1 and hence the first digit (and the next number in the series) in the next triplet will be 1.

Q) 4, 3, 6, 2, 2, 8, 4, 4, 5, 6, 3, ?

solution

(4,3,6,2) (4×3 = 6×2)

(2,8,4,4) (2×8 = 4×4)

We notice that the product of the first two digits in the quadruplet is equal to the product of the last two numbers in the quadruplet.

(5,6,3,?)

Hence the solution is 10

We cant stress enough the importance of having this solution method in your arsenal as you approach the IPAT. In our experience, we have seen disproportionate number of series questions solvable through the pairing approach. As a serious test taker, if you want to get quick on these types of questions do check out our IPAT practice guide here – it has all the practice you need to ace the IPAT. Let’s next move on to another very important type of the Ipat numeric series question – The interleaved series.